ÔÚµçÁ¦¹øÂ¯µÈ¹¤Òµ³¡¾°ÖУ¬£¬£¬µ±KÐÍÅâ³¥µ¼ÏßÒò³¤¶È¡¢¡¢¡¢ÇéÐÎζȻòµç´Å×ÌÈŵ¼ÖÂÕÉÁ¿Îó²îʱ£¬£¬£¬¿Éͨ¹ýÊÖ¶¯Åâ³¥ÒªÁìÐÞÕýÎó²î¡£¡£¡£¹Å°åÊÖ¶¯Åâ³¥Ö÷Òª»ùÓÚÈȵçżµÄÖÐÐÄζȶ¨ÂÉ£¬£¬£¬Í¨¹ýÅÌËã»ò²é±íÐÞÕýÀä¶ËζÈת±äÒýÈëµÄÎó²î¡£¡£¡£ÒÔÏÂÊÇÏêϸ·½·¨¼°Ê¾Àý£º
Ò»¡¢¡¢¡¢ÊÖ¶¯Åâ³¥ÔÀí
ƾ֤ÖÐÐÄζȶ¨ÂÉ£¬£¬£¬ÈȵçżµÄÈÈµç¶¯ÊÆ ¿ÉÌåÏÖΪ£º
E(T,0)=E(T,T0)+E(T0,0)
ÆäÖУº
£ºÈȶËÏÖʵζȣ¨´ý²âζȣ©£»
£ºÀä¶ËÏÖʵζȣ¨·Ç0¡æ£©£»
£ºÅâ³¥µ¼ÏßÕÉÁ¿µÄÈÈµç¶¯ÊÆ£»
£ºÀä¶ËζÈΪ ʱµÄÀíÂÛÈÈµç¶¯ÊÆ£¨Í¨Ì«¹ý¶È±í²éµÃ£©¡£¡£¡£
ÊÖ¶¯Å⳥ĿµÄ£ºÍ¨¹ýÕÉÁ¿Àä¶ËÎÂ¶È £¬£¬£¬ÅÌËã £¬£¬£¬²¢½«ÆäÓë Ïà¼Ó£¬£¬£¬»ñµÃÐÞÕýºóµÄÈÈµç¶¯ÊÆ £¬£¬£¬ÔÙ·´²é·Ö¶È±í»ñµÃÈȶËÎÂ¶È ¡£¡£¡£
¶þ¡¢¡¢¡¢ÊÖ¶¯Åâ³¥·½·¨
1. ÕÉÁ¿Àä¶ËζÈ
¹¤¾ß£ºÊ¹Óø߾«¶Èζȼƣ¨È粬µç×èζȼơ¢¡¢¡¢Êý×Öζȼƣ©ÕÉÁ¿Åâ³¥µ¼ÏßÀä¶ËËùÔÚÇéÐεÄÏÖʵÎÂ¶È ¡£¡£¡£
×¢ÖØ£ºÀä¶ËζÈÐèÎȹÌÇÒÔȳƣ¬£¬£¬×èÖ¹¾Ö²¿Î¶Ȳ¨¶¯Ó°ÏìÕÉÁ¿Ð§¹û¡£¡£¡£ÈôÀä¶ËζÈÎÞ·¨ºã¶¨£¬£¬£¬Ðè·Ö¶ÎÕÉÁ¿²¢È¡Æ½¾ùÖµ¡£¡£¡£
2. ²éKÐÍÈȵçż·Ö¶È±í»ñÈ¡
·Ö¶È±í£ºÆ¾Ö¤Àä¶ËÎÂ¶È £¬£¬£¬´ÓKÐÍÈȵçż·Ö¶È±íÖвéÕÒ¶ÔÓ¦µÄÈÈµç¶¯ÊÆ ¡£¡£¡£
ʾÀý£ºÈô £¬£¬£¬²é·Ö¶È±íµÃ ¡£¡£¡£
·Ö¶È±íȪԴ£º¿É²Î¿¼¹ú¼Ò±ê×¼£¨ÈçGB/T 16839.1-2018£©»òÒÇÆ÷³§ÉÌÌṩµÄ·Ö¶È±í¡£¡£¡£
3. ÕÉÁ¿Åâ³¥µ¼ÏßÊä³öµçÊÆ
¹¤¾ß£ºÊ¹Óø߾«¶ÈºÁ·ü±íÕÉÁ¿Åâ³¥µ¼ÏßÀä¶ËÓëÈȶËÖ®¼äµÄÈÈµç¶¯ÊÆ ¡£¡£¡£
ʾÀý£ºÈôÕÉÁ¿µÃ ¡£¡£¡£
×¢ÖØ£ºÕÉÁ¿Ê±ÐèÈ·±£Åâ³¥µ¼ÏßÅþÁ¬×¼È·£¨¼«ÐÔ²»¿É·´½Ó£©£¬£¬£¬ÇÒ×èÖ¹µç´Å×ÌÈÅ£¨ÈçÔ¶Àë±äƵÆ÷¡¢¡¢¡¢µç»úµÈ×°±¸£©¡£¡£¡£
4. ÅÌËãÐÞÕýºóµÄÈÈµç¶¯ÊÆ
E(T,0)=E(T,T0)+E(T0,0)
ʾÀý£º
E(T,0)=12.345mV+0.798mV=13.143mV
5. ·´²é·Ö¶È±í»ñÈ¡ÈȶËζÈ
²Ù×÷£ºÆ¾Ö¤ÐÞÕýºóµÄÈÈµç¶¯ÊÆ £¬£¬£¬´ÓKÐÍÈȵçż·Ö¶È±íÖз´ºË¶ÔÓ¦µÄÈȶËÎÂ¶È ¡£¡£¡£
ʾÀý£º²é·Ö¶È±íµÃ £¬£¬£¬¡£¡£¡£Í¨¹ýÏßÐÔ²åÖµÅÌË㣺
T=300¡æ+12.898?12.20713.143?12.207¡Á10¡æ¡Ö315.4¡æ
Èý¡¢¡¢¡¢ÊÖ¶¯Å⳥ʾÀý
³¡¾°£ºµçÁ¦¹øÂ¯ÖУ¬£¬£¬KÐÍÅâ³¥µ¼ÏßÀä¶ËÎÂ¶È £¬£¬£¬ÕÉÁ¿µÃÅâ³¥µ¼ÏßÊä³öµçÊÆ ¡£¡£¡£
Åâ³¥·½·¨£º
²é·Ö¶È±íµÃ £»
ÅÌËãÐÞÕýºóµçÊÆ£º
E(T,0)=10.567mV+1.000mV=11.567mV
·´²é·Ö¶È±íµÃ £¬£¬£¬¡£¡£¡£Í¨¹ýÏßÐÔ²åÖµÅÌË㣺
T=280¡æ+11.927?11.37711.567?11.377¡Á10¡æ¡Ö283.5¡æ
Ч¹û£ºÈȶËÏÖʵζÈԼΪ283.5¡æ£¬£¬£¬½ÏδÅ⳥ʱ£¨Ö±½Ó²é ¶ÔӦζȣ©Îó²îïÔÌÔ¼5¡æ¡£¡£¡£
ËÄ¡¢¡¢¡¢×¢ÖØÊÂÏî
·Ö¶È±í¾«¶È£ºÊ¹Óø߾«¶È·Ö¶È±í£¨ÖÁÉÙ±£´æ3λСÊý£©£¬£¬£¬×èÖ¹²é±íÎó²îÀÛ»ý¡£¡£¡£
Àä¶ËζÈÕÉÁ¿£ºÀä¶ËζÈÕÉÁ¿Îó²î»áÖ±½Óת´ïÖÁ×îÖÕЧ¹û£¬£¬£¬ÐèʹÓþ«¶È¡Ý¡À0.5¡æµÄζȼơ£¡£¡£
ÏßÐÔ²åÖµ£ºÈô·Ö¶È±íΪÀëÉ¢Êý¾Ý£¬£¬£¬Ðèͨ¹ýÏßÐÔ²åÖµÌá¸ßÅÌË㾫¶È¡£¡£¡£
Åâ³¥µ¼Ïß³¤¶È£ºÈôÅâ³¥µ¼Ïß¹ý³¤£¨ÈçÁè¼Ý15Ã×£©£¬£¬£¬ÐèÏÈÆÀ¹ÀÐźÅË¥¼õºÍµç´Å×ÌÈÅÓ°Ï죬£¬£¬ÐëҪʱ¼ÓװζȱäËÍÆ÷»òÇл»ÖÁ4-20mAÐźŴ«Êä¡£¡£¡£
¼«ÐÔÅþÁ¬£ºÅâ³¥µ¼Ïß¼«ÐÔ·´½Ó»áµ¼ÖÂÈÈµç¶¯ÊÆÆ«ÏòÏà·´£¬£¬£¬ÕÉÁ¿ÖµÆ«µÍ£¬£¬£¬ÐèÑÏ¿á¼ì²éÅþÁ¬Æ«Ïò¡£¡£¡£
Ïà¹ØÄÚÈÝ
- »·±£×èȼµçÀÂ×°ÖÃÌæ»»ÖÜÆÚզȷ¶¨£¿
- »·±£×èȼµçÀÂ×°ÖùÊÕÏÅŲéÕ¦×ö£¿
- »·±£×èȼµçÀÂ×°ÖÃÖÊÁ¿¼ì²âÕ¦¾ÙÐУ¿
- »·±£×èȼµçÀÂ×°Ö÷À³±Õ¦´¦Àí£¿
- »·±£×èȼµçÀÂ×°Öõç´Å×ÌÈÅÕ¦·À»¤£¿
- »·±£×èȼµçÀÂ×°ÖÃÎïÁªÍøÕ¦Ó¦Óã¿
- »·±£×èȼµçÀÂ×°ÖôóÊý¾ÝզʹÓã¿
- »·±£×èȼµçÀ½»Áª¹¤ÒÕ²ÎÊýÎó²îÕ¦µ÷½â£¿
- »·±£×èȼµçÀµ¼Ìå½ØÃæ»ýËõË®Ôõô½â¾ö£¿
- µÍÑ̵ͱµçÀº£ÄÚÈÏÖ¤±ê×¼£¿

